C语言答案谭浩强第7章(3)

tran[j]=219-ch[j];

else

tran[j]=ch[j];

j++;

}

n=j;

printf(“\n : ”);

for (j=0; j<n; j++)

putchar(tran[j]);

printf(“\n”);

}

: R droo erhrg Xsrmz mvcg dvvp.

: R droo erhrg Xsrmz mvcg dvvp.

: I will visit China next week.

7.13 , , strcat

N-S 7.11

C语言答案谭浩强

:

main()

{char s1[80]; s2[80];

int i=0, j=0;

printf(“\n 1: ”);

scanf(“%s”, s1);

printf(“\n 2: ”);

scanf(“%s”, s2);

while (s1[i]!= ‘\0’)

i++;

while (s2[j]!= ‘\0’)

s1[i++]=s2[j++];

s1[i]= ‘\0’;

printf(“ : %s”, s1);

}

1: country

2: side

: countryside

7.14 , s1 s2 , s1>s2, ; s1=s2, 0; s1<s2, strcmp gets ASCII , ‘A’ ‘C’ , ‘A’< ‘C’ , ‘A’ ‘C’ ASCII 2, “-2” : “And” “Aid” , 2 , ‘n’ ‘i’ 5, “5”

N-S 7.12

C语言答案谭浩强

#include <stdio.h>

main()

{

int i, resu;

char s1[100], s2[100];

printf(“\n 1: ”);

scanf(“%s”, s1);

printf(“\n 2: ”);

scanf(“%s”, s2);

i=0;

while (s1[i]==s2[i] && s1[i]!= ‘\0’)

i++;

if (s1[i]== ‘\0’ && s2[i]== ‘\0’)

resu=0;

else

resu=s1[i]-s2[i];

printf(“\n : %d. \n”, resu);

}

1: aid

2: and

: -5.

7.15 , s2 s1 strcpy , ‘ 0’ ‘ 0’

#include <stdio.h>

main()

{char s1[80], s2[80];

int i;

printf(“ s2: ”);

C语言答案谭浩强

gets(s2);

for (i=0; i<=strlen(s2); i++) s1[i]=s2[i];

s1[i]= ‘\0’;

printf(“ s1: %s\n”, s1); }

s2:student

s1:student