C语言答案谭浩强第7章

C语言答案谭浩强

7

7.1 100

N-S 7.1

#include <math.h>

main()

{int i, j, n, a[101];

for (i=1; i<=100; i++)

a[i]=i;

for (i=2; i<=sqrt(100); i++)

for (j=i+1; j<=100; j++)

if (a[i]!=0 && a[j]!=0)

if (a[j]%a[i]==0)

a[j]=0;

printf(“\n”);

for (i=2; i<=100; i++)

{if (a[i]!=0)

{printf(“%5d”, a[i]);

n++;

C语言答案谭浩强

}

if (n%10==0)

printf(“\n”);

}

}

2 3 5 7 11 13 17 19 23 29

31 37 42 43 47 53 59 61 67 71

73 79 83 89 97

7.2 10 ( )

10 a[1]~a[10] a[1] a[2]~a[10] a[1] a[2]~a[10] a[2]~a[10] a[1] a[1] a[1] 10 a[2] a[3]~a[10] a[2] a[3]~a[10] a[3]~a[10] a[2] a[2] a[2] 10 9 a[1] a[10] N-S 7.2

main()

{int i, j, min, temp, a[11];

printf(“ : \n”);

for (i=1; i<=10; i++)

{printf(“a[%d]=”, i);

scanf(“%d”, &a[i]); /* 10 */

}

printf(“\n”);

for (i=1; i<=10; i++)

printf(“%5d”, a[i]); /* 10 */

printf(“\n”);

for (i=1; i<=9; i++) /* 7 10 */

C语言答案谭浩强

{min=i;

for (j=i+1; i<=10; j++)

if (a[min]>a[j]) min=j;

temp=a[i]; a[i]=a[min]; a[min]=temp; /* a[i+1]~a[10] a[i] */

}

printf(“ : \n”);

for (i=1; i<=10; i++)

printf(“%5d”, a[i]); /* 10 */

}

:

a[1]=6

a[2]=90

a[3]=45

a[4]=56

a[5]=1

a[6]=15

a[7]=44

a[8]=78

a[9]=58

a[10]=101

6 90 45 56 1 15 44 78 58 101

:

1 6 15 44 45 56 58 78 90 101

7.3 3 3

main()

{int a[3][3], i, j, sum=0;

printf(“ : \n”);

for (i=0; i<3; i++)

for (j=0; j<3; j++)

scanf(“%d”, &a[i][j]);

for (i=0; i<3; i++)

sum+=a[i][i];

printf(“sum=%5d”, sum);

}

:

1 2 3 4 5 6 7 8 9

sum= 15

7.4

N-S 7.3

C语言答案谭浩强

main()

{int a[11]={1, 4, 6, 9, 13, 16, 19, 28, 40, 100};

int temp1, temp2, number, end, i, j;

printf(“a : \n”);

for (i=0; i<10; i++)

printf(“%5d”, a[i]);

printf(“\n”);

printf(“ : ”);

scanf(“%d”, &number);

end=a[9];

if (number>end)

a[10]=number;

else

{for (i=0; i<10; i++)

if (a[i]>number)

{temp1=a[i]; a[i]=number;

for (j=i+1; j<11; j++)

{temp2=a[j]; a[j]=temp1; temp1=temp2; }

}

}

printf(“ : \n”);

for (i=0; i<11; i++)

printf(“%5d”, a[i]);

}

a :

1 4 6 9 13 16 19 28 40 100

C语言答案谭浩强

:5

1 4 5 6 9 13 16 19 28 40 100

7.5 , 8,6,5,4,1 1,4,5,6,8

N-S 7.4

#define N 5

main()

{int a[N], i, temp;

printf(“ a : \n”);

for (i=0; i<N; i++)

scanf(“%d”, &a[i]);

printf(“a :\n”);

for (i=0; i<N; i++)

printf(“%5d”, a[i]);

for (i=0; i<N/2; i++)

{temp=a[i]; a[i]=a[N-i-1]; a[N-i-1]=temp; }

printf(“ a : \n”);

for (i=0; i<N; i++)

printf(“%5d”, a[i]);

printf(“\n”);}

a :

8 6 5 4 1

a :

8 6 5 4 1

a :

1 4 5 6 8

7.6 ( 10 )

1

1 1

1 2 1

1 3 3 1

1 4 6 4 1

1 5 10 10 5 1

………………

C语言答案谭浩强

(a+b)

1

1

3

N-S 7.5 1 2 3 n

:

#define N 11

main()

{int i, j, a[N][N];

for (i=1; i<N; i++)

{a[i][i]=1;

a[i][1]=1;

}

for (i=3; i<N; i++)

for (j=2; j<i-1; j++)

a[i][j]=a[i-1][j-1]+a[i-1][j];

for (i=1; i<N; i++)

{for (j=1; j<=i; j++)

printf(“%6d”, a[i][j]);

printf(“\n”);

}

}

1

1 1

1 2 1

1 3 3 1

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