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2016年5月福州市普通高中毕业班综合测试文科数学试题(word 版含(3)

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导读: 6分 由(Ⅰ)知,DF 又因为AB 4,所以PD AD 2, 2016年5月7日福州高三质检文科数学含答案 7分 所以AP 2AF 2, 8分 所以 ADP为正三角形, 9分 所以AO PD,且AO 因为AB 平面PAD,AB//CD, 所以CD 平面PAD. 10分 因为A

··········································· 6分 由(Ⅰ)知,DF ·

又因为AB 4,所以PD AD 2,

2016年5月7日福州高三质检文科数学含答案

················································· 7分 所以AP 2AF 2, ·

············································································ 8分 所以 ADP为正三角形, ·

····································································· 9分 所以AO

PD,且AO ·

因为AB 平面PAD,AB//CD,

所以CD 平面PAD. ·············································································· 10分 因为AO 平面PAD, 所以CD AO, ······················································································ 11分 又因为PD CD D,所以AO 平面PCD.

所以三棱锥A

PCD ································································ 12分 (20)本小题考查点与圆、直线与椭圆的位置关系等基础知识,考查运算求解能力、推理论证能力,考查数形结合思想、化归与转化思想等.满分12分.

解法一:

(Ⅰ)依题意得,2c a 4, ···················································· 2分 所以b2 a2 c2 1, ·················································································· 3分

x2

y2 1. ·所以E的方程为····································································· 4分 4

(Ⅱ)点A在 M外.理由如下: ································································ 5分 设P x1,y1 ,Q x2,y2 ,

y k(x 1),由 2得(1 4k2)x2 8k2x 4k2 4 0, ············································ 6分 2

x 4y 4,

所以, ( 8k2)2 4(4k2 1)(4k2 4) 48k2 16 0,

8k24k2 4

所以x1 x2 ,x1x2 . ····························································· 8分

1 4k21 4k2

因为AP x1 2,y1 ,AQ x2 2,y2 ,

所以

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