C语言程序设计现代方法第16章答案(2)

scanf("%d", &number);

i = find_part(number, inv, np);

if (i >= 0) {

printf("Part name: %s\n", inv[i].name);

printf("Quantity on hand: %d\n", inv[i].on_hand); } else

printf("Part not found.\n");

}

/********************************************************** * update: Prompts the user to enter a part number. * * Prints an error message if the part can't be * * found in the inv array; otherwise, prompts the * * user to enter change in quantity on hand and * * updates the array. * **********************************************************/ void update(struct part inv[], int np)

{

int i, number, change;

printf("Enter part number: ");

scanf("%d", &number);

i = find_part(number, inv, np);

if (i >= 0) {

printf("Enter change in quantity on hand: ");

scanf("%d", &change);

inv[i].on_hand += change;

} else

printf("Part not found.\n");

}

/********************************************************** * print: Prints a listing of all parts in the inv array, *

* showing the part number, part name, and * * quantity on hand. Parts are printed in the * * order in which they were entered into the * * array. * **********************************************************/ void print(const struct part inv[], int np)

{

int i;

printf("Part Number Part Name " "Quantity on Hand\n");

for (i = 0; i < np; i++)

printf("%7d %-25s%11d\n", inv[i].number,

inv[i].name, inv[i].on_hand);

}