IPv4 ClassicalSubnettingPractice_KEY

Classical Subnetting Practice

KEY

Part 1

Given each network address, and for the subnet required provide the following: Subnet Address:

Subnet Mask: (both dotted-decimal and slash notation):

Host Range:

Broadcast Address:

Default Gateway:

Note: If the question refershosts, subnets sizes must be as small as possible but still satisfy the required number.

1. 10.0.0.0

a. Create 117 subnets and 255 hosts per subnet

b. Provide answers for Subnet 2

Subnet Address:10.0.4.0

Subnet Mask: /23 or 255.255.254.0

Host Range: 10.0.4.1 – 10.0.5.254

Broadcast Address: 10.0.5.255

Default Gateway: 10.0.5.254

2. 172.31.0.0

a. Create 63 subnets with least 127 hosts

b. Provide answers for 2rd subnet

Subnet Address:172.31.1.0

Subnet Mask: /24 or 255.255.255.0

Host Range: 172.31.1.1 – 172.3131.254

Broadcast Address: 172.31.1.255

Default Gateway: 172.31.1.254

3. 10.0.0.0

a. Create 120 subnets

b. Provide answers for Subnet 4

Subnet Address:10.8.0.0

Subnet Mask: /15 or 255.254.0.0

Host Range: 10.8.1.1 – 10.9.255.254

Broadcast Address: 10.9.255.255

Default Gateway: 10.9.255.254

NETE1200 2017/18 Subnetting Practice 2

4. 192.168.0.0

a. 7 subnets and 31 hosts per

b. Provide answers for 4nd subnet

Not Doable

- Need 6 host bits (25-2 = 30)

- Only 2 subnet bits availab;e

- 22 = 4 – only 4 subnets can be created

5. 172.18.0.0

a. 195 hosts per subnet and 131 subnets

b. Provide answers for 5th subnet

Subnet Address:17.18.4.0

Subnet Mask: /24 or 255.255.255.0

Host Range: 172.18.4.1 – 172.18.4.254

Broadcast Address: 172.18.4.255

Default Gateway: 172.18.4.255

Part 2

Given each IPv4 address, provide the following:

Subnet Address:

Subnet Mask:

Host Range:

Address Type: host, network, broadcast, default gateway

1. 19

2.168.111.111/29

Subnet Address: 192.168.111.104

Subnet Mask: 255.255.255.248

Host Range:192.168.111.105 – 192.168.111.110

Address Type: Broadcast Address

2. 172.27.27.159/27

Subnet Address: 172.27.27.128

Subnet Mask: 255.255.255.224

Host Range:172.27.27.129 – 172.27.27.128

Address Type: Broadcast Address

NETE1200 2017/18 Subnetting Practice 3 3. 10.185.194.224/28

Subnet Address: 10.185.195.224

Subnet Mask: 255.255.255.240

Host Range:10.185.194.225 – 10.185.194.254

Address Type: Subnet Address

4. 192.168.64.62/30

Subnet Address: 192.168.64.60

Subnet Mask: 255.255.255.252

Host Range:192.168.64.61 – 192.168.64.62

Address Type: Host Address

5. 172.22.222.0/18

Subnet Address: 172.22.192.0

Subnet Mask: 255.255.192.0

Host Range:172.22.192.1 – 172.22.254.254

Address Type: Host Address

6. 172.22.224.0/19

Subnet Address: 172.22.224.0

Subnet Mask: 255.255.224.0

Host Range:172.22.224.1 – 172.22.254.254

Address Type: Subnet Address

7. 10.200.187.254/23

Subnet Address: 10.200.186.0

Subnet Mask: 255.255.254.0

Host Range:10.200.186.1 – 10.200.187.254

Address Type: Host Address (Default Gateway)

8. 10.255.255.126/25

Subnet Address: 10.255.255.0

Subnet Mask: 255.255.255.128

Host Range:10.255.255.1 – 10.255.255.126

Address Type: Host Address (Default Gateway)

NETE1200 2017/18 Subnetting Practice 4 Part 3

Identify whether the following pairs of addresses are on the same network/subnet.

1. 19

2.168.1.62/28

192.168.1.64/28

Different:

192.168.1.62/28 is on Subnet 192.168.1.48

192.168.1.64 is Subnet Address of next subnet

2. 172.26.20

3.1/23

172.26.204.1/23

Different:

172.26.203.1 is on Subnet 172.16.202.0

172.16.204.1 is on Subnet 172.16.204.0

3. 192.168.1.6/29

192.168.1.9/30

Different

To be on same subnet they must share same mask

4. 10.133.31.254/19

10.133.32.1/19

Different

10.133.21.254/19 is on Subnet 10.133.0.0

10.133.32.1/19 is on Subnet 10.133.32.0

5. 172.18.175.254/20

172.18.161.1/20

Same

They bare both on Subnet 172.18.160.0