【例5.11】多继承中构造函数和析构函数的调用顺序

【例5.11】多继承中构造函数和析构函数的调用顺序

#include<iostream.h>

class OBJ1

{

public:

OBJ1(){cout<<"OBJ1\n";}

~OBJ1(){cout<<"destructing OBJ1"<<endl;}

};

class OBJ2

{

public:

OBJ2(){ cout<<"OBJ2\n"; }

~OBJ2(){cout<<"destructing OBJ2"<<endl;}

};

class Base1

{

public:

Base1(){ cout<<"Base1\n"; }

~Base1(){cout<<"destructing Base1"<<endl;}

};

class Base2

{

public:

Base2(){ cout<<"Base2\n"; }

~Base2(){cout<<"destructing Base2"<<endl;}

};

class Base3

{

public:

Base3(){ cout<<"Base3\n"; }

~Base3(){cout<<"destructing Base3"<<endl;}

};

class Base4{

public:

Base4(){ cout<<"Base4\n"; }

~Base4(){cout<<"destructing Base4"<<endl;}

};

class Derived:public Base1,virtual public Base2,public Base3,virtual public Base4

{

public:

Derived():Base4(),Base3(),Base2(),Base1(),obj2(),obj1() {

cout <<"Derived ok.\n";

}

~Derived(){cout<<"destructing Derived"<<endl;} protected:

OBJ1 obj1;

OBJ2 obj2;

};

void main()

{

Derived aa;

}

程序的运行结果为：

Base2

Base4

Base1

Base3

OBJ1

OBJ2

Derived ok.

destructing Derived

destructing OBJ2

destructing OBJ1 destructing Base3 destructing Base1 destructing Base4 destructing Base2