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78. 5 ·Ö (6731) 6731

[´ð] ps= 2¡Á 2 ??/ (R1)¡¯= 16Pa, ps¡¯= 2¡Á 2??/ (R2)¡¯= 8 Pa¡£ ÏàÁ¬ºóСÅݱäС, ´óÅݱä´ó, ÒòСÅÝÖÐѹÁ¦´ó¡£

79. 5 ·Ö (6741)

6741

¡¯

[´ð] ln (pr / p0) = 2? M /( R T R?) = 0.3218 (3·Ö) pr/p0=1.3797 pr= 139.79 kPa¢« (2·Ö)

80. 2 ·Ö (6750)

6750

[´ð] h = 2 ??/( ?gR¡¯) h1/ h2= (?1/?1)/ (?2/?2)= 1

h1= h2= 1.5¡Á10-2 m (2·Ö)

81. 5 ·Ö (6770)

6770

[´ð] ps? lnprp02?r?2?0.072 753.0?10?6?48.5 kPa £¨2·Ö£©

?3?7?2?MRTr??2?0.072 75?18.02?1038.314?293.15?10?3?10?0.003 586

pr?2346 P a £¨3·Ö£©

82. 5 ·Ö (6772)

6772

[´ð] ?(Ca2SO4-H2O)?RTr?2Mlncrc

?8.314?298.15?3.0?102?136?10?1?3?7?2960N?m?1ln18.2?10?3?315.33?10

?1.39 N?m £¨5·Ö£©

83. 10 ·Ö (6774)

6774

[´ð] ps?2? ?Vm?M £¨4·Ö£©

r2?psr2??Vm lnpr2?MpsVmp???RTr??0RTrRT

7?5 ?1.39?10?1.84?108.314?313.15?0.098 22

prp?1.103

0 pr?p0p?100%?10.3% 0

84. 10 ·Ö (6775) 6775

[´ð] (1) ?1T21vapHRTm?Tlnp2?mol? 2?T1p?42.74 kJ1 (2) lnprp?2?M?2?0.058 85?18.02?10?30RT?r8.314?373.15?950?(?10?6)??0.007 196

pr?101.25 k P a (3) p2?0.058 85s?2?r?1?10?6 kPa?117.7 kPa ÕôÆøÊܵĸ½¼ÓѹÁ¦´óÓÚÕôÆøµÄѹÁ¦£¬ÆøÅݲ»ÄÜÎȶ¨´æÔÚ¡£

85. 10 ·Ö (6777) 6777

[´ð] (1) ?vapHm?88 J?K_1?mol?1T29.454 kJ?mol?1b? £¨4·Ö£©

2·Ö£©

£¨2·Ö£©

£¨3·Ö£© £¨3·Ö£©

£¨3·Ö£© £¨3·Ö£©

£¨ ?vapHm?11?294 54?11? (2) ln??????????1.2976

p1RTT8.314334.7298.15???12?p2 p2?27.68 k P a £¨3·Ö£©

(3) lnprp0?2?MRT?r?2?0.026 67?119.5?10?3?88.314?298.15?1480?1?10?0.173 75

pr?32.93 k P a £¨4·Ö£©

86. 10 ·Ö (6778)

6778

[´ð] 298.15 KʱÕý¶¡´¼µÄÕôÆøѹΪp0 lnp2aHpm?p??v?1?1???438 ?22?11R?1?TT8.314??39029???154.16 3512??8. p0=p2=1.576 kPa lnpr?M2?0.02?61p?20RT?r?0.0748.31?4298?.15?8?06?91?11.093 34 ? pr=10.89 kPa

87. 10 ·Ö (6779) 6779

[´ð] (1) ?vapHm?88 J?K?1?mol?1T?1b?31.09 kJ?mol (2) lnp2?p?vapHm?R?1?1??T? 11T2? p2?14.3 k P a £¨25¡æʱ±½µÄÕôÆøѹ£© lnprM2?0.028 ?22?7?8310p?2?0RT?r?8.31?4298?.15?87?3?71?100.020 34 pr?14.59 k P a (3) p2?s?r?564.4 kPa

88. 10 ·Ö (6780) 6780

[´ð] p2?s?r?2?0.071 972?10?6 Pa?71 970 Pa £¨10·Ö£© 3·Ö£©

2·Ö£© £¨3·Ö£© £¨2·Ö£©

2·Ö£©

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